Revision Notes MCQ Bank SAQ Bank Study Cards Courses Teachers Blog

Bond Energies

A concise revision guide to bond energies: what bond energy means, why reactions are exothermic or endothermic, calculating ΔH from bond energies, and why the answers differ from Hess’s law values, for Cambridge International A Level Chemistry.

AS Level
Topic 5: Chemical Energetics
9701 Papers 1 and 2
Cambridge International specification5 spec points in this lesson
  • 5.1.4
  • 5.1.5
  • 5.1.6-a
  • 5.1.6-b
  • 5.2.2(b)
What these spec points say
  • 5.1.4 understand that energy transfers occur during chemical reactions because of the breaking and making of chemical bonds
  • 5.1.5 use bond energies (ΔH positive, i.e. bond breaking) to calculate enthalpy change of reaction, ΔHr
  • 5.1.6-a understand that some bond energies are exact
  • 5.1.6-b understand that some bond energies are averages
  • 5.2.2(b) carry out calculations using cycles and relevant energy terms, including use of bond energy data

Bond Enthalpies: Breaking In, Making Out

Choose a step to watch hydrogen and chlorine react: energy goes in to break the old bonds, comes out as the new bonds form, and the difference is the enthalpy change.

Drag to rotate
Step
View

Hydrogen Chlorine Carbon Electron Energy in Energy out Enthalpy bar

© Dr. Mohammed Al-Fatah – onlinelearningsystem.net

Bonds broken and made when methane burns

Break every bond in CH4 and 2O2, form the bonds in CO2 and 2H2O, and add up the bond energies to find the enthalpy change of combustion.

Drag to rotate
ΔH = +2632 − 3450 = −818 kJ mol−1
Step
View

Carbon Hydrogen Oxygen Bond Bond breaking, energy in Bond forming, energy out Bond angle, ΔH

© Dr. Mohammed Al-Fatah – onlinelearningsystem.net

Before you start

GCSE Recap: Energy In and Energy Out

Before you start, check the GCSE rule this page puts numbers on.

1

What Bond Energy Means

The bond energy is the energy needed to break one mole of a given covalent bond in molecules in the gaseous state. Breaking a bond always needs energy, so bond energies are always positive; making the same bond releases the same amount of energy.

Some bond energies are exact. For a diatomic molecule such as H₂ there is only one bond in one environment, so its value is exact. Others, such as the C–H bond, are averages taken over many different molecules.

Bond energies for common bonds: multiple bonds are stronger than single bonds between the same atoms, and N≡N is the strongest shown.

Definition: Bond energy is the energy required to break one mole of a particular covalent bond in the gaseous state.

Check your understanding

Quick Check: Exact or Mean?

Drag the words into place to decide which of two quoted values is exact.

2

Why Reactions Are Exothermic or Endothermic

Every reaction breaks some bonds and makes others. Bond breaking is endothermic and bond making is exothermic. The overall enthalpy change depends on which is larger:

  • If more energy is released making the bonds in the products than is absorbed breaking the bonds in the reactants, the reaction is exothermic.
  • If more energy is absorbed breaking bonds than is released making them, the reaction is endothermic.

Key idea: ΔH = energy absorbed breaking bonds − energy released making bonds. A negative answer means the products are held by stronger bonds overall.

Check your understanding

Quick Check: Reading the Sign

In each round, choose the one statement that is accurate.

3

Calculating ΔH from Bond Energies

Key equation: ΔH = Σ(bond energies of bonds broken) − Σ(bond energies of bonds made)

Worked example. Calculate the enthalpy change for the combustion of methane, CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g), using C–H 410, O=O 496, C=O 805 and O–H 460 kJ mol⁻¹.

BondsNumberEnergy / kJ
Broken: C–H44 × 410 = 1640
Broken: O=O22 × 496 = 992
Total broken+2632
Made: C=O22 × 805 = 1610
Made: O–H44 × 460 = 1840
Total made3450

ΔH = 2632 − 3450 = −818 kJ mol⁻¹

Counting every bond always works. Where a bond is unchanged on both sides you may leave it out and count only the bonds that break and form.

The unchanged bonds cancel, so the two routes give the same answer, and the shorter one saves a great deal of time.

Exam tip: Data books differ slightly in the values they quote, so always use the values printed in the question.

Exam focus: Draw out the displayed formulae first and count every bond. Most lost marks come from missing a bond, not from the arithmetic.

Check your understanding

Quick Check: Calculate an Enthalpy Change

Work the calculation out on paper with the data in the question, then choose your answer.

4

Why Bond Energy Values Differ from Hess Values

The data book enthalpy change of combustion of methane is −890 kJ mol⁻¹, but the bond energy calculation gives −818 kJ mol⁻¹. There are two reasons:

  1. Average values are used. The C–H value is an average over many compounds, not the exact value for methane, and the same is true of C=O and O–H.
  2. Everything is assumed to be gaseous. Bond energies apply to gaseous molecules, but standard enthalpy changes of combustion form liquid water. Condensing the water releases extra energy that the calculation leaves out. Put plainly, this calculation gives the value for H₂O(g), while the data book enthalpy change of combustion is quoted for H₂O(l).

Exam sentence: Values calculated from bond energies are less accurate than those from Hess’s law because bond energies are averages over many compounds and apply only to substances in the gaseous state.

The combustion of methane from data book values and from bond energies, and the two reasons the answers differ.

Check your understanding

Quick Check: Explain the Difference

Write a short explanation, then compare it with the mark points and the model answer.

5

Finding a Bond Energy from ΔH

The same equation can be rearranged to find one unknown bond value when ΔH and the others are known.

Worked example. H₂(g) + Cl₂(g) → 2HCl(g), ΔH = −184 kJ mol⁻¹. Using H–H 436 and Cl–Cl 242 kJ mol⁻¹, find the H–Cl value.

  1. ΔH = (436 + 242) − 2E(H–Cl)
  2. −184 = 678 − 2E(H–Cl)
  3. 2E(H–Cl) = 862, so E(H–Cl) = 431 kJ mol⁻¹ (3 significant figures)

With the unknown on the left. H₂(g) + I₂(g) → 2HI(g), ΔH = −11 kJ mol⁻¹, using H–H 436 and H–I 299 kJ mol⁻¹. Bonds broken are 436 + E(I–I); bonds made are 2 × 299 = 598. So −11 = 436 + E(I–I) − 598, giving E(I–I) = 151 kJ mol⁻¹.

Remember: Two moles of HCl form, so two H–Cl bonds are made. Divide by the number of bonds of the unknown type at the end.

Check your understanding

Quick Check: Find the Unknown Bond

Rearrange the key equation to find the missing value, then choose your answer.

6

Common Exam Points

Define bond energy

The energy needed to break one mole of a particular covalent bond in the gaseous state.

Calculate ΔH from bond energies

Bonds broken minus bonds made; count every bond from the displayed formulae.

Explain why the answer differs from the data book value

Bond energies are averages, and the calculation assumes all species are gases.

Do not say

“Bond making needs energy”; “bond energies are exact for every molecule”.

FAQs

Use these quick answers to check the bond energies ideas and calculations.

Why are bond energies always positive?

They are defined for breaking bonds, and breaking a bond always needs energy.

How do I calculate ΔH from bond values?

Add up the bond energies of all the bonds broken, add up those of all the bonds made, and subtract: bonds broken minus bonds made.

Why is my answer different from the data book value?

The bond energies are averages over many compounds, and the method assumes every substance is a gas, whereas standard values may involve liquids.

What makes a reaction exothermic in terms of bonds?

More energy is released making the bonds in the products than is absorbed breaking the bonds in the reactants.

Are any bond values exact?

Yes, for diatomic molecules such as H₂ or Cl₂, where there is only one bond in one environment. Bonds found in many compounds, such as C–H, have average values.

Dr. Mohammed Al-Fatah

Written by:
Dr. Mohammed Al-Fatah

Chemistry specialist revision notes for A Level Chemistry.

View LinkedIn Profile

Copyright notice: This OLS revision content, including the explanations, layout, diagrams, tables and embedded learning structure, is authored for Online Learning System by Dr. Mohammed Al-Fatah. It may not be copied, reproduced, redistributed or adapted without written permission.