Revision Notes MCQ Bank SAQ Bank Study Cards Courses Teachers Blog

Measuring pH and Finding Ka by Experiment

A concise revision guide to pH experiments: using and calibrating a pH meter, the pH of strong and weak acids, bases and salts, how dilution affects strong and weak acids, and finding Ka by experiment, plus why weak acids have less exothermic enthalpies of neutralisation.

Paper 1 and 3
Topic 12: Acid-base Equilibria
9CH0/01
Edexcel specification9 spec points in this lesson
  • 12.14i
  • 12.14ii-a
  • 12.14ii-b
  • 12.14ii-c
  • 12.14ii-d
  • 12.14ii-e
  • 12.14ii-f
  • 12.15
  • 12.23
What these spec points say
  • 12.14i be able to analyse data from the following experiments: measuring the pH of a variety of substances, e.g. equimolar solutions of strong and weak acids, strong and weak bases, and salts
  • 12.14ii-a be able to analyse data comparing pH of a strong acid after dilution 10 times
  • 12.14ii-b be able to analyse data comparing pH of a weak acid after dilution 10 times
  • 12.14ii-c be able to analyse data comparing pH of a strong acid after dilution 100 times
  • 12.14ii-d be able to analyse data comparing pH of a weak acid after dilution 100 times
  • 12.14ii-e be able to analyse data comparing pH of a strong acid after dilution 1000 times
  • 12.14ii-f be able to analyse data comparing pH of a weak acid after dilution 1000 times
  • 12.15 be able to calculate Ka for a weak acid from experimental data given the pH of a solution containing a known mass of acid
  • 12.23 understand why there is a difference in enthalpy changes of neutralisation values for strong and weak acids
Before you start

GCSE Recap: Acids, Alkalis and Their Strength

Three quick questions on the GCSE ideas this page builds on.

2

Using a pH Meter

A pH meter measures pH to 2 decimal places, far more precisely than universal indicator, which gives only about the nearest whole number.

  1. Calibrate: dip the electrode into buffer solutions of known pH, usually 4.00, 7.00 and 10.00, and adjust the meter to read each value.
  2. Rinse the electrode with distilled water and blot it gently dry.
  3. Place the electrode in the solution and stir gently.
  4. Wait until the reading is steady, then record it to 2 decimal places.
  5. Rinse between every solution, and note the temperature: pH changes with temperature.
  • Calibration corrects for drift in the electrode, so the readings are accurate.
  • Rinsing stops one solution contaminating the next.
  • Store the electrode in its storage solution; a dry glass electrode gives slow, unreliable readings.

Exam wording: “Calibrate the pH meter using buffer solutions of known pH. Rinse the electrode with distilled water between measurements and wait for a steady reading.”

Check your understanding

Quick Check: Trusting a pH Reading

Pick the one accurate statement in each set about a measurement that may have gone wrong.

3

The pH of Acids, Bases and Salts

Comparing solutions of the same concentration shows the difference between strong and weak acids and bases, and that many salts are not neutral.

0.100 mol dm⁻³ solutionTypepH at 298 K
HClstrong acid1.00
CH₃COOHweak acid2.88
NaOHstrong base13.00
NH₃weak baseabout 11.1
CH₃COONasalt of a weak acid and a strong baseabout 8.9
NH₄Clsalt of a strong acid and a weak baseabout 5.1
NaClsalt of a strong acid and a strong base7.00

Why some salts are not neutral

  • Sodium ethanoate is basic. Ethanoate ions accept protons from water: CH₃COO⁻ + H₂O ⇌ CH₃COOH + OH⁻, so [OH⁻] rises.
  • Ammonium chloride is acidic. Ammonium ions donate protons: NH₄⁺ ⇌ NH₃ + H⁺, so [H⁺] rises.
  • Sodium chloride is neutral. Neither Na⁺ nor Cl⁻ reacts with water, so [H⁺] = [OH⁻].

Using a pH meter: calibration with buffers of pH 4.00, 7.00 and 10.00, rinsing, stirring and reading to 2 decimal places, with the pH of seven 0.100 mol dm⁻³ acids, bases and salts.

Key idea: At the same concentration a weak acid has a higher pH than a strong acid, and a weak base a lower pH than a strong base. The salt of a weak acid is basic; the salt of a weak base is acidic.

4

Diluting Strong and Weak Acids

Diluting each acid by 10, 100 and 1000 times shows another clear difference between strong and weak acids.

DilutionConcentration / mol dm⁻³pH of HClpH of CH₃COOH
None0.1001.002.88
×100.01002.003.38
×1000.001003.003.88
×10000.0001004.00about 4.4
  • Strong acid: [H⁺] equals the acid concentration, so each tenfold dilution lowers [H⁺] ten times and raises the pH by exactly 1.
  • Weak acid: [H⁺] = √(Ka × [HA]), so a tenfold dilution lowers [H⁺] only by √10, about 3.16 times, and the pH rises by about 0.5.
  • As a weak acid is diluted, a larger fraction of it dissociates, which is why its pH rises more slowly.

Diluting hydrochloric acid and ethanoic acid 10, 100 and 1000 times: the strong acid rises one pH unit each time, the weak acid only about half a unit.

Exam focus: A pH rise of 1 for each tenfold dilution identifies a strong acid. A rise of about 0.5 identifies a weak acid. At high dilution the ×1000 value shows the approximations beginning to fail.

Check your understanding

Check: pH Data for Acids, Bases and Salts

Interpret pH readings for equimolar acids, bases and salts and for diluted strong and weak acids, explaining each value, for substances not used on this page.

Check your understanding

Quick Check: What Dilution Reveals

Use each new set of invented readings to make a fast decision.

5

Finding Ka by Experiment

Method 1: half-neutralisation

  1. Titrate 25.0 cm³ of the weak acid with NaOH(aq), using phenolphthalein, to find the end point volume, V.
  2. To a fresh 25.0 cm³ of the acid, add exactly (V) / (2) of the same NaOH(aq).
  3. Mix, then measure the pH with a calibrated pH meter.
  4. Half the acid is now A⁻, so [HA] = [A⁻] and pH = pKa.

Example. The half-neutralised solution reads pH 4.20. So pKa = 4.20 and Ka = 10⁻⁴·²⁰ = 6.31 × 10⁻⁵ mol dm⁻³.

The whole titration curve can be plotted instead, and the pH read at half the equivalence volume.

Method 2: the pH of a known concentration

0.370 g of a weak monobasic acid, HA (Mr = 74.0), is dissolved in water and made up to 100 cm³. The pH is 3.10. Calculate Ka.

Step 1.
Moles of HA = (0.370) / (74.0) = 5.00 × 10⁻³ mol
Concentration = (5.00 × 10⁻³) / (0.100) = 0.0500 mol dm⁻³
Step 2.
[H⁺] = 10⁻³·¹⁰ = 7.94 × 10⁻⁴ mol dm⁻³
Assume [A⁻] = [H⁺] and [HA] = 0.0500 mol dm⁻³

Answer. Ka = ([H⁺]²) / ([HA]) = ((7.94 × 10⁻⁴)²) / (0.0500) = 1.26 × 10⁻⁵ mol dm⁻³

Two ways to find Ka: the half-neutralisation method, where the measured pH equals pKa, and measuring the pH of a weak acid of known concentration made from a weighed mass.

MethodAdvantageLimitation
Half-neutralisationno assumption about how much acid dissociatesneeds an accurate end point and volume
Known concentrationone solution and one readingrelies on the weak acid approximations

Exam focus: A pH reading to 2 decimal places limits Ka to about 2 significant figures. Calibrate the meter and keep the temperature constant: Ka changes with temperature.

Check your understanding

Check: Finding Ka by Experiment

Use half-neutralisation readings and the pH of solutions of known concentration to calculate Ka and pKa, and evaluate the methods, with data not used on this page.

6

Enthalpy of Neutralisation: Strong and Weak Acids

The enthalpy change of neutralisation is the enthalpy change when an acid and an alkali react to form 1 mol of water, under standard conditions.

Acid (with NaOH)TypeΔH neutralisation / kJ mol⁻¹
HClstrongabout −57
HNO₃strongabout −57
CH₃COOHweakabout −56
HCNvery weakabout −12
  • For every strong acid the reaction is the same: H⁺(aq) + OH⁻(aq) → H₂O(l). So the values are almost identical.
  • A weak acid is mostly undissociated. It must dissociate as it reacts, and some of the energy released is used to do this.
  • So the enthalpy change is less exothermic for a weak acid. The effect is small for ethanoic acid but large for HCN.

Exam wording: “Strong acids are fully dissociated, so each reaction is H⁺ + OH⁻ → H₂O. A weak acid must dissociate as it is neutralised; this uses energy, so less heat is given out.”

7

Common Exam Points

Say

  • “Calibrate the pH meter with buffer solutions of known pH before use.”
  • “At half-neutralisation [HA] = [A⁻], so pKa equals the measured pH.”
  • “The ethanoate ion accepts a proton from water, producing OH⁻, so sodium ethanoate solution is alkaline.”

Do not say

  • “All salts are neutral.”
  • “Diluting any acid ten times raises its pH by 1” (only for a strong acid).
  • “A higher pH means a stronger acid” (compare acids only at the same concentration).

Watch for

  • Data tables of pH against dilution: decide strong or weak from the size of each rise.
  • Ka from a mass: convert the mass to moles and then to a concentration before using the pH.
  • Evaluation: name calibration, rinsing, temperature and a steady reading as ways to improve accuracy.

FAQs

Use these quick answers to check pH measurements and finding Ka by experiment.

Why must a pH meter be calibrated?

The electrode drifts over time, so its readings become inaccurate. Dipping it into buffer solutions of known pH, usually 4.00, 7.00 and 10.00, and adjusting the meter to match makes later readings accurate.

Why is sodium ethanoate solution alkaline?

Ethanoate ions accept protons from water: CH₃COO⁻ + H₂O ⇌ CH₃COOH + OH⁻. This raises [OH⁻], so the pH is about 8.9 at 0.100 mol dm⁻³. The salt of a weak acid and a strong base is basic.

How does dilution show whether an acid is strong or weak?

A tenfold dilution raises the pH of a strong acid by exactly 1. For a weak acid [H⁺] falls only by √10, because a larger fraction dissociates on dilution, so the pH rises by only about 0.5.

How does the half-neutralisation method find Ka?

Titrate the acid to find the end point volume, then add exactly half that volume of the alkali to a fresh portion of the acid. Half the acid is now A⁻, so [HA] = [A⁻] and the measured pH equals pKa.

Why is the enthalpy of neutralisation of a weak acid less exothermic?

A weak acid is mostly undissociated, so it must dissociate as it reacts, and this uses some of the energy released. Strong acids all react as H⁺ + OH⁻ → H₂O, giving about −57 kJ mol⁻¹.

Dr. Mohammed Al-Fatah

Written by:
Dr. Mohammed Al-Fatah

Chemistry specialist revision notes for A Level Chemistry.

View LinkedIn Profile

Copyright notice: This OLS revision content, including the explanations, layout, diagrams, tables and embedded learning structure, is authored for Online Learning System by Dr. Mohammed Al-Fatah. It may not be copied, reproduced, redistributed or adapted without written permission.