Electrophilic Addition Mechanism
A concise revision guide to addition reactions of alkenes, electrophiles, electron-rich π bonds and why the carbon-carbon double bond is the reactive centre in alkene chemistry.
GCSE Recap: What Alkenes Do
Three quick questions on the reactions of alkenes that you met at GCSE.
Addition Reactions of Alkenes
An addition reaction is a reaction in which two reactant molecules combine to form a single product molecule.
Alkenes commonly undergo addition reactions because their carbon-carbon double bond can be broken and replaced by new single bonds.
This is why the C=C bond is the functional group that controls the characteristic reactions of alkenes.
Key idea: In an alkene addition reaction, atoms add across the C=C double bond and only one organic product molecule is formed.
Addition across a double bond
The double bond opens up, allowing new atoms or groups to attach to the two carbon atoms from the original C=C bond.
Quick Check: Addition or Not?
Decide quickly whether each equation shows an addition reaction.
Why the π Bond Reacts
In an alkene, the π bond is weaker than the σ bond, so it requires less energy to break during a reaction.
The π bond also contains a region of high electron density. This exposed electron density is especially attractive to electron-seeking species.
Because the π bond is both weaker and more exposed than a σ bond, it is particularly susceptible to attack by electrophiles.
Exam focus: Link alkene reactivity to the exposed, electron-rich π bond rather than simply saying that alkenes have a double bond.
Electron-rich π bond
The π bond forms exposed electron density above and below the molecular plane, making the alkene attractive to electrophiles.
Quick Check: Spot the Errors
Click the five wrong words in a student's description of the π bond.
Electrophiles
An electrophile is an electron pair acceptor.
Electrophiles are attracted to regions of high electron density. In alkenes, this means the electrophile is drawn towards the electron-rich π bond.
This attraction begins the electrophilic addition mechanism.
Electrophile: A species that accepts an electron pair from an electron-rich region during a chemical reaction.
Quick Check: Find the Electrophile
Identify the electrophile in a reagent that this page has not used.
The Electrophilic Addition Mechanism
In electrophilic addition, the π bond breaks and new single bonds are formed. The electrophile accepts an electron pair from the alkene.
At this stage, students must be careful with curly arrows. A curly arrow shows the movement of an electron pair, so the arrow should start from a bond or lone pair, not from a positive charge.
1. Attraction
The electrophile is attracted to the high electron density in the π bond.
2. Bond breaking
The π bond breaks because it is weaker than the σ bond.
3. New bonds form
New single bonds form to give an addition product.
Remember: Electrophilic addition happens because the π bond is electron-rich, exposed and relatively easy to break.
Quick Check: Order the Mechanism
Put the events of an electrophilic addition you have not seen into the correct order.
Quick Check: Hydrogen Iodide and Cyclohexene
In each round, pick the one accurate statement about this addition.
The Three AQA Mechanisms
AQA 3.3.4.2 asks for the electrophilic addition mechanism of alkenes with three reagents: HBr, H2SO4 and Br2. The pattern is the same each time: the π bond attacks the electrophile, a carbocation forms, and a negative ion then attacks the carbocation.
| Reagent | Electrophile | Negative ion formed | Product with ethene |
|---|---|---|---|
| HBr | Hδ+ of the polar H-Br bond | Br– | Bromoethane |
| H2SO4 (concentrated) | Hδ+ of an O-H bond | HSO4– (hydrogensulfate ion) | Ethyl hydrogensulfate, then ethanol on hydrolysis |
| Br2 | Brδ+ of the induced dipole | Br– | 1,2-dibromoethane |
Bromine is a non-polar molecule, so the electrophile is created when the alkene approaches: electron density in the π bond repels the electrons in the Br-Br bond and induces a dipole. The nearer bromine atom becomes Brδ+ and the Br-Br bond then breaks heterolytically.
Exam focus: Draw every curly arrow from an electron pair: the π bond to the electrophile, the polar bond to the atom that becomes the negative ion, and the lone pair on the negative ion to the carbocation. Show the carbocation with its positive charge on the correct carbon atom.
Quick Check: Three Reagents, New Alkenes
Apply the three mechanisms to but-2-ene and cyclohexene.
Exam Link: Why Alkenes React This Way
Exam answers should connect three ideas: the alkene contains a C=C bond, the π bond has high electron density, and electrophiles are attracted to this electron-rich region.
It is not enough to write that alkenes are reactive because they have a double bond. The explanation needs to identify the role of the π bond and the electrophile.
| Exam phrase | Why it matters | Common mistake to avoid |
|---|---|---|
| π bond has high electron density | Explains why an electrophile is attracted to the alkene. | Only saying that the double bond is reactive. |
| Electrophile accepts an electron pair | Links the definition of electrophile to the mechanism. | Calling the electrophile an electron donor. |
| π bond breaks and new single bonds form | Explains why the reaction is an addition reaction. | Describing substitution instead of addition. |
Quick Check: Explain Why the Alkene Reacts
Write a short explanation, then compare it with the mark points and the model answer.
Master Alkenes for AQA A Level Chemistry
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Some ionic radii are shown.
| Ion | Ionic radius / nm |
|---|---|
| Na+ | 0.102 |
| K+ | 0.138 |
| F− | 0.133 |
| Cl− | 0.180 |
Which compound has the strongest ionic bonding?
Explain why the metallic bonding in magnesium is much stronger than that in sodium.
Copyright notice: This OLS revision content, including the explanations, layout, diagrams, tables and embedded learning structure, is authored for Online Learning System by Dr. Mohammed Al-Fatah. It may not be copied, reproduced, redistributed or adapted without written permission.
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