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Producing Alkanes

A concise Cambridge International AS Level Chemistry revision guide to the two ways of producing alkanes named in 14.1.1: the addition of hydrogen to an alkene with a platinum or nickel catalyst and heat, and the cracking of a longer-chain alkane by heating with aluminium oxide.

AS Level
Topic 14: Hydrocarbons
9701 Papers 1 and 2
Dr. Mohammed Al-Fatah

Written by: Dr. Mohammed Al-Fatah

Chemistry specialist revision notes for A Level Chemistry.

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Before you start

GCSE Recap: Formulae and Balancing

Before you start, check the general formulae and the atom counting this page depends on.

1

Two Routes to an Alkane

Cambridge 14.1.1 asks you to recall the reagents and conditions for two reactions that produce alkanes. Both are met again elsewhere in the syllabus, but here the alkane is the product you are asked about.

RouteStarting materialReagents and conditionsType of reactionExample
HydrogenationAn alkeneH2(g) with a Pt or Ni catalyst, heatAdditionCH3CH=CH2 + H2 → CH3CH2CH3
CrackingA longer-chain alkaneHeat with Al2O3Thermal decomposition (C-C bonds broken)C10H22 → C8H18 + C2H4

Producing alkanes: adding hydrogen across the C=C bond of an alkene, or cracking a longer alkane over hot aluminium oxide.

Key idea: Hydrogenation makes an alkane from a smaller, unsaturated molecule; cracking makes an alkane (and an alkene) from a larger, saturated one.

Check your understanding

Quick Check: Picking the Right Route

Decide which starting material and route would give one pure alkane.

2

Hydrogenation of Alkenes

Hydrogen adds across the C=C double bond of an alkene in the presence of a platinum or nickel catalyst with heat. The π bond breaks, two new C-H σ bonds form, and the product is the saturated alkane with the same carbon skeleton. The catalyst provides a surface on which the H2 molecule is split into atoms that add to the alkene.

Because the carbon skeleton is unchanged, the alkane formed is easy to predict: but-1-ene and but-2-ene both give butane; 2-methylpropene gives 2-methylpropane. The reaction is used industrially to make saturated fats from vegetable oils, where the same catalyst and conditions apply.

Exam sentence: Alkenes are converted to alkanes by addition of hydrogen: H2(g) with a platinum or nickel catalyst and heat.

Check your understanding

Quick Check: Predict the Product

Work each answer out on paper, then flip the card to compare.

3

Cracking a Longer Alkane

Heating a long-chain alkane with aluminium oxide, Al2O3, breaks a C-C bond and produces a shorter alkane together with an alkene. The Cambridge wording is simply “heat with Al2O3“; the oxide acts as a catalyst. Any C-C bond can break, so a mixture forms, but in each equation the carbon and hydrogen atoms must balance and one product is an alkene.

  • C12H26 → C7H16 + C5H10 (heptane and pentene)
  • C12H26 → C8H18 + 2C2H4 (octane and two ethene molecules)

Cracking is also how refineries obtain more useful alkanes and alkenes of lower relative molecular mass from the heavy fractions of crude oil (14.1.4); the full industrial context is on the Cracking page.

Exam focus: Quote the conditions exactly as the syllabus does: heat with Al2O3 for cracking; H2 with Pt or Ni and heat for hydrogenation.

Check your understanding

Quick Check: Finish the Cracking Equation

Balance the equation to find the formula of the missing alkene.

Check your understanding

Quick Check: Pick the Accurate Statement

In each round, choose the one statement that is accurate.

4

Common Exam Mistakes

  • Giving the hydrogenation catalyst as “a catalyst” without naming platinum or nickel.
  • Writing a cracking equation with two alkanes as products. One product must be an alkene for the hydrogen atoms to balance.
  • Describing hydrogenation as a substitution. It is an addition reaction: the alkene gains two hydrogen atoms and nothing is lost.
  • Confusing the cracking catalyst (Al2O3) with the hydrogenation catalyst (Pt or Ni).

Exam sentence: Alkanes are produced by hydrogenating an alkene with H2 over Pt or Ni with heat, or by cracking a longer alkane by heating with Al2O3.

Cambridge International AS and A Level Chemistry Topics 13 and 14.1 Introduction to Organic Chemistry and Alkanes interactive course banner
Cambridge 9701 | Topics 13 and 14.1 Course
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Master Introduction to Organic Chemistry and Alkanes for Cambridge International AS & A Level Chemistry

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Free Radical Substitution FAQs

These questions summarise the core exam points on alkane substitution and free radicals.

Why are alkanes usually unreactive?

Alkanes are usually unreactive because they contain strong C-C and C-H bonds. These bonds require a large amount of energy to break.

What condition is needed for alkanes to react with chlorine?

Ultraviolet light is needed. UV light provides enough energy to break the Cl-Cl bond by homolytic fission, forming chlorine radicals.

What is a free radical?

A free radical is a species with an unpaired electron. The unpaired electron is usually represented using a dot, such as Cl•.

Why is the reaction called substitution?

It is called substitution because a hydrogen atom in the alkane is replaced by a halogen atom.

Why can a mixture of products form?

After the first substitution, the haloalkane product can undergo further substitution. This can replace more hydrogen atoms and produce a mixture of chlorinated products.

Copyright notice: This OLS revision content, including the explanations, layout, diagrams, tables and embedded learning structure, is authored for Online Learning System by Dr. Mohammed Al-Fatah. It may not be copied, reproduced, redistributed or adapted without written permission.