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Choosing Solvents

A concise revision guide to how intermolecular forces decide the choice of solvent: hydration of ions, alcohols dissolving in water by hydrogen bonding, why water is a poor solvent for halogenoalkanes, and like-dissolves-like for non-aqueous solvents, for Edexcel International A Level Chemistry.

Exam board: Edexcel International
Unit 2: WCH12/01
Topic 7: Intermolecular Forces
Edexcel International specification4 spec points in this lesson
  • 7.6i
  • 7.6ii
  • 7.6iii
  • 7.6iv
What these spec points say
  • 7.6i understand factors that influence the choice of solvents, including: water, to dissolve some ionic compounds, in terms of the hydration of the ions
  • 7.6ii understand factors that influence the choice of solvents, including: water, to dissolve simple alcohols, in terms of hydrogen bonding
  • 7.6iii understand factors that influence the choice of solvents, including: water, as a poor solvent for compounds (to include polar molecules such as halogenoalkane), in terms of inability to form hydrogen bonds
  • 7.6iv understand factors that influence the choice of solvents, including: non-aqueous solvents, for compounds that have similar intermolecular forces to those in the solvent
Before you start

GCSE Recap: Solutes, Solvents and Layers

Three quick questions on the GCSE ideas about dissolving that this page builds on.

1

What Decides Whether Something Dissolves

A substance dissolves in a solvent when the attractions formed between solute and solvent particles are strong enough to compensate for the attractions broken within the solute and within the solvent.

Dissolving is therefore a balance of intermolecular forces. The rule of thumb “like dissolves like” simply means that the new solute-solvent attractions must be of a similar kind and strength to the ones being lost.

The two do not have to balance exactly: a small energy cost can still be paid. That is why solids such as ammonium nitrate dissolve even though the solution gets colder as they do.

Three questions decide the outcome: what holds the solute together (ionic lattice, hydrogen bonds, permanent dipoles or London forces), what holds the solvent together, and what the two can form with each other.

Key idea: Energy is needed to break solute-solute and solvent-solvent attractions; energy is released when solute-solvent attractions form. Dissolving happens when the two roughly balance.

Check your understanding

Quick Check: What Holds the Solute Together?

Pick the strongest attraction holding each solute together.

2

Water Dissolving Ionic Compounds: Hydration of Ions

Water is polar: its oxygen is δ- and its hydrogens δ+.

When an ionic solid such as sodium chloride is placed in water, the δ- oxygen atoms of water molecules are attracted to the Na⁺ ions and the δ+ hydrogen atoms to the Cl⁻ ions.

Each ion that leaves the lattice becomes surrounded by a shell of correctly oriented water molecules. This is hydration, and the attractions formed are called ion-dipole attractions.

The energy released by hydrating the ions is comparable to the energy needed to break up the lattice, so sodium chloride dissolves.

Magnesium oxide does not dissolve appreciably. Its ions carry 2+ and 2- charges and are small, so they pull on each other far more strongly than Na⁺ and Cl⁻ do.

Breaking that lattice costs far more energy than hydrating the ions can release.

Hydration: water molecules orient their δ- oxygens towards cations and their δ+ hydrogens towards anions, and the attractions formed pay for breaking the lattice.

Exam sentence: Sodium chloride dissolves in water because the δ- oxygen atoms of water molecules attract the Na⁺ ions and the δ+ hydrogen atoms attract the Cl⁻ ions; the energy released when the ions are hydrated compensates for the energy needed to break the ionic lattice.

Check your understanding

Quick Check: One Salt Dissolves, One Does Not

Drag the words into the gaps to explain why one salt dissolves and the other does not.

3

Water Dissolving Alcohols: Hydrogen Bonding

Methanol, ethanol and propan-1-ol mix with water in all proportions because the O-H group of the alcohol forms hydrogen bonds with water molecules.

The hydrogen bonds formed between alcohol and water are similar in strength to the hydrogen bonds broken within the water and within the alcohol, so there is no barrier to mixing.

As the carbon chain grows the alcohol becomes less soluble. Methanol, ethanol and propan-1-ol mix in all proportions; butan-1-ol dissolves only to about 7 g per 100 g of water and hexan-1-ol to less than 1 g.

The long non-polar chain can only form London forces with water. To make room for it, water must break hydrogen bonds that the chain cannot replace.

The hydrocarbon part outweighs the single O-H group.

Ethanol forming hydrogen bonds with water molecules Chloroethane next to water molecules, showing that it does not form hydrogen bonds with water

Ethanol dissolves because its O-H group replaces the water hydrogen bonds it disrupts; chloroethane cannot form hydrogen bonds with water, so it does not dissolve.

Key idea: Small alcohols are miscible with water because they hydrogen bond with it; solubility falls as the non-polar chain lengthens.

Check your understanding

Quick Check: Two Alcohols, Same Electrons

Choose the statement that explains the difference in solubility.

4

Why Water Is a Poor Solvent for Halogenoalkanes

Halogenoalkanes such as chloroethane are polar molecules: the C-Cl bond has a permanent dipole. Yet they are almost insoluble in water.

Key idea: The reason is that a halogenoalkane cannot form hydrogen bonds with water: it has no hydrogen bonded to N, O or F, and the halogen atom is a poor acceptor of hydrogen bonds.

To dissolve, the halogenoalkane would have to break hydrogen bonds between water molecules to make space for itself. The weak permanent dipole-permanent dipole interactions it could form with water would not pay back that energy.

The same argument applies to many polar molecules without an O-H or N-H group, and it explains why “polar” does not automatically mean “soluble in water”.

The question is always whether the solute can form hydrogen bonds with water, or at least attractions comparable to the ones it disrupts.

Key idea: A solute does not have to donate a hydrogen bond to dissolve: accepting one is enough.

Propanone has no O-H, but the lone pairs on its C=O oxygen accept hydrogen bonds from the δ+ hydrogens of water. This is why it mixes with water in all proportions.

A halogen atom accepts far too weakly for that.

SolutePolar?Can hydrogen bond with water?Soluble in water?
Ethanol, C₂H₅OHyesyes, O-Hmiscible
Propanone, CH₃COCH₃yesyes, C=O accepts from watermiscible
Chloroethane, C₂H₅Clyesnoalmost insoluble
Hexane, C₆H₁₄nonoinsoluble
Sodium chlorideionicions are hydratedsoluble

Exam sentence: Chloroethane does not dissolve in water because chloroethane molecules cannot form hydrogen bonds with water molecules; the hydrogen bonds between water molecules that would have to be broken are not replaced by attractions of similar strength.

Check your understanding

Quick Check: Pick the Accurate Statement

Choose the one accurate statement about polar solutes and water in each round.

5

Non-Aqueous Solvents: Like Dissolves Like

Substances that water cannot dissolve usually dissolve in a solvent whose intermolecular forces match their own.

A non-polar solute dissolves in a non-polar solvent because the London forces broken between solute molecules and between solvent molecules are replaced by London forces of similar strength between solute and solvent.

Iodine dissolves readily in hexane or cyclohexane but only slightly in water. Grease and candle wax dissolve in hexane; halogenoalkanes dissolve in hexane and in ethanol.

SoluteForces within the soluteGood solventPoor solvent
Iodine, I₂London forceshexane, cyclohexanewater
Candle wax (long alkanes)London forceshexane, white spiritwater
Chloroethanepermanent dipole-permanent dipole interactions and London forceshexane, ethanolwater
Sodium chlorideionic latticewaterhexane
Sugar (sucrose)hydrogen bonds (many O-H)waterhexane

The choice of solvent matters in practical chemistry. An organic product is extracted from an aqueous mixture with a non-polar solvent in a separating funnel.

The product dissolves in the organic layer and the ionic impurities stay in the water.

Two layers form because neither liquid dissolves in the other: the water molecules hold on to each other by hydrogen bonds that a non-polar solvent cannot replace.

The organic layer is usually the upper one, because most organic solvents are less dense than water. You can identify the layers by adding a little more water and seeing which one grows.

The lower layer is run out of the tap first.

Ethanol is useful because it is both at once: the O-H group hydrogen bonds like water, while the ethyl group sits happily among non-polar molecules. Ethanol therefore dissolves some ionic solids and many organic ones, which is why it appears in the table as a solvent for chloroethane.

Exam focus: When asked to choose or justify a solvent, name the strongest force in the solute, name the strongest force in the candidate solvent, and say whether the solute-solvent attractions formed can replace those broken.

A solute dissolves in a solvent whose intermolecular forces match its own, which is why an organic product can be extracted into a non-polar layer away from ionic impurities.

Check your understanding

Quick Check: Choose the Solvent

Click every substance that dissolves better in a non-polar solvent than in water.

Check your understanding

Quick Check: Dissolving from Start to Finish

Pick the one accurate statement in each round to check the whole page.

6

Common Exam Points

Explain why sodium chloride dissolves in water

δ- oxygen of water attracts Na⁺, δ+ hydrogen attracts Cl⁻; the energy released on hydrating the ions compensates for the energy needed to break the lattice.

Explain why ethanol mixes with water but hexane does not

Ethanol forms hydrogen bonds with water; hexane can only form London forces, which cannot replace the hydrogen bonds broken in water.

Explain why a polar halogenoalkane is insoluble in water

It cannot hydrogen bond with water; the attractions it forms do not compensate for the water hydrogen bonds broken.

Suggest a solvent for iodine

A non-polar solvent such as hexane, because both are held by London forces only.

FAQs

Use these quick answers to check how intermolecular forces decide what dissolves in what.

Why does sodium chloride dissolve in water?

The δ- oxygen atoms of water molecules are attracted to the Na⁺ ions and the δ+ hydrogen atoms to the Cl⁻ ions, so the ions become hydrated. The energy released by hydration compensates for the energy needed to break up the ionic lattice.

Why do small alcohols mix with water?

The O-H group of the alcohol forms hydrogen bonds with water molecules that are similar in strength to the ones being broken, so there is no barrier to mixing. Solubility falls as the carbon chain lengthens.

Why does a polar halogenoalkane not dissolve in water?

It has no hydrogen bonded to N, O or F, so it cannot form hydrogen bonds with water. The water-water hydrogen bonds that must be broken to make room for it are not replaced by attractions of similar strength.

What does “like dissolves like” actually mean?

It means the solute-solvent attractions formed must be of the same kind and strength as the solute-solute and solvent-solvent attractions broken. Iodine dissolves in hexane because both are held only by London forces.

Does polar always mean water-soluble?

No. Chloroethane is polar but almost insoluble in water, because its dipole is not enough to replace the hydrogen bonds it disrupts. The question to ask is whether the solute can hydrogen bond with water.

Dr. Mohammed Al-Fatah

Written by: Dr. Mohammed Al-Fatah

Chemistry specialist revision notes for A Level Chemistry.

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Copyright notice: This OLS revision content, including the explanations, layout, diagrams, tables and embedded learning structure, is authored for Online Learning System by Dr. Mohammed Al-Fatah. It may not be copied, reproduced, redistributed or adapted without written permission.